Russian Doll (2019)

On the night of her 36th birthday, Nadia meets an untimely end ... then suddenly finds herself back at the party her friends threw for her.

Confused and hung over, Nadia tries to piece together what happened the night before. She tracks down Wardog, the drug dealer with the Israeli joints.

Nadia's hunt for clues leads her to a Yeshiva school -- but she needs John's help. Out searching for Oatmeal, Nadia befriends a homeless man.

Meticulous as always, Alan steadies himself for a rendez-vous with his girlfriend. Meanwhile, Nadia's latest discovery sends her reeling.

Perturbed by the changes in his routine, Alan shows up at Nadia's birthday party. Nadia tries to make amends to John, and Alan confronts Mike.

Nadia and Alan try to figure out how they're connected. Alan can't remember his first death, so Nadia follows him over the course of his night.

As the present begins to unravel, Nadia's troubled past comes back to haunt her, and Alan worries they're running out of time.

Nadia and Alan look for each other and finally cross paths at the deli. Something's not right -- but they're not giving up on each other.

Nadia's 40th birthday is a few days away, and she's planning to celebrate it quietly with Alan. Then something really strange happens.

While hopping around the city searching for missing Krugerrands, Nadia runs into a familiar face who lends her a hand.

Nadia learns an intriguing fact about the family fortune that sends her on a quest for clues — and her situation takes a bizarre new turn.

Alan gets in touch with his roots in Berlin. On a trip to Budapest, Nadia and Maxine wind up at a mind-bending house party.

Nadia tracks down the stolen valuables and formulates a plan to secure her family's future. But she comes to a grim realization.

After the weirdest subway ride yet, Nadia navigates a puzzling predicament. Meanwhile, Alan desperately tries to find Nadia.

On Nadia's birthday, she and Alan reunite in a familiar place. But they clash over how to handle the future (and the past).